Answer: 31,365
Explanation:
Given : The number of horror films = 15
The number of comedies = 18
Then , the number of different combinations of 4 movies can he rent if he wants at least two comedies is given by :-
![^(18)C_2* ^(15)C_2+^(18)C_3* ^(15)C_1+^(18)C_4* ^(15)C_0\\\\=(18!)/(2!(18-2)!)*(15!)/(2!(15-2)!)+(18!)/(3!(18-3)!)*(15!)/(1!(15-1)!)+(18!)/(4!(18-4)!)*(15!)/(0!(15-0)!)\\\\=16065+12240+3060=31365](https://img.qammunity.org/2020/formulas/mathematics/college/tblaoapv3bbn1eklbmys59fjaoom5po2yr.png)
Hence, the number of different combinations of 4 movies can he rent if he wants at least two comedies = 31,365