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What is the smallest positive integer that will make x^x > 500,000? What

is the largest negative integer that will make x^(-x) > 500,000?

User Embedded C
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2 Answers

1 vote

Answer:

Smallest positive integer value for
x^x>500000 is,

x = 7,

Largest negative integer value for
x^(-x)>500000 is,

x = -8

Explanation:

If
x^x>500000

By graphing calculator,


x>6.83

Thus, the smallest possible positive integer value of x is 7,

Now,


x^(-x)>500000

Possible negative integer values of x are -6, -7 and -8,

If x = -6, -7, and -8,


(-6)^(6)=46656


(-7)^(7)=-823543


(-8)^(8)=16777216


\because 16777216 > 500000

Thus, the largest negative integer value of the inequality
x^(-x)>500000 is,

x = -8.

User Nategoose
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6.2k points
4 votes

Answer:

For
x^x > 500,000
x=7

For
x^((-x)) > 500,000
x=-7

Explanation:

We need to find the smallest positive whole number that satisfies the inequality:


x^x > 500,000

We tested with x = 6


6^6=46,656\\\\46,656 > 500,000

Inequality is not met because
46,656 < 500,000

We test with the following integer x = 7

Then we have that:


7^7=823,543\\\\823,543 > 500,000

Then the smallest positive integer that will make
x^x > 500,000 is 7 because Inequality is met.

In the same way the largest negative integer that will make
x^((-x)) >500000 is
x=-7 Beacuse
7^(-(-7))=823,543>500,000

User Stefan Scherer
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6.0k points