Question

Examine the first two steps used to solve the equation.

3 4 (20y − 8) + 5 = 1 2 y + 1 4 (20y + 8)
15y − 6 + 5 = 1 2 y + 5y + 2
15y − 1 = 11 2 y + 2

Which would be a good third step to solve the equation?
A. Combine like terms 11/2 and 2
B. Distribute 15 to each term on the left side.
C. Subtract 11/2y from each side of the equation.
D. Divide each side of the equation by 2.

Answer 1

C. Subtract 11/2y from each side of the equation.

Explanation:

Answer 2

C.

Explanation:

Your fractions are missing there fraction bars:

3/4 (20y − 8) + 5 = 1/2 y + 1/4 (20y + 8)

15y − 6 + 5 = 1/2 y + 5y + 2

15y − 1 = 11/2 y + 2

A. 11/2y and 2 aren't like terms because one contains the variable y and the other contains no variable

B. The distribute property can't be used there because you don't have 15(y-1) you have 15y-1

C. Subtracting 11/2y sounds like a good step because there is a y term on the opposing side.

15y-1=11/2y+2

Subtracing 11/2y on both sides

9.5y-1=2

That looks pretty good because then you would add 1 on both sides giving:

9.5y =3

Last step would get the y by itself which is dividing both sides by 9.5 giving you 6/19.

D. You could actually do this but it doesn't help you get x by itself. The equation would look like this: 15/2 y-1/2=11/4 y+1