Answer:
y-22=14(x-1)
Explanation:
Since we are looking for a line parallel to y=14x-3 then we are looking for a line that has the same slope as y=14x-3.
The slope of y=14x-3 is 14.
So the slope of our line is 14.
So we know our equation is in the form y=14x+b.
We can find b by using a point (x,y) on the line. We know (x,y)=(1,22) is a point on the line we are looking for.
So I'm going to replace x with 1 and y with 22 in the equation y=14x+b giving me
22=14(1)+b
22=14 +b
Subtract 14 on both sides
8=b
The equation of the line is y=14x+8. That is slope-intercept form. I will leave this here just in case you are curious of this.
I was do point-slope form now since that is what your question says.
We know the slope is 14 so m=14.
The point-slope form is y-y1=m(x-x1).
We know (x1,y1)=(1,22) so now we substitute.
y-22=14(x-1)