Final answer:
The oxidation number for Cu(s) is 0. An oxidizing agent gains electrons. Na+ is formed from the reduction of Na(s). The oxidation number for Hg(????) is usually +2. A reducing agent gains electrons. Zn2+ is formed from the oxidation of Zn(s).
Step-by-step explanation:
In this question, we are given several statements about oxidation numbers and oxidizing/reducing agents. Let's go through each statement one by one:
- The oxidation number for Cu(s) is +2. This statement is incorrect. The oxidation number for Cu(s) is 0 because it is in its elemental form.
- An oxidizing agent gains electrons. This statement is correct. An oxidizing agent is a substance that causes another substance to lose electrons.
- Na+ is formed from the reduction of Na(s). This statement is correct. Na+ is formed when sodium loses one electron and gets oxidized to Na+.
- The oxidation number for Hg(????) is 0. This statement is incorrect. The oxidation number for Hg is usually +2, but it can also be +1 in some cases.
- A reducing agent gains electrons. This statement is correct. A reducing agent is a substance that causes another substance to gain electrons.
- Zn2+ is formed from the oxidation of Zn(s). This statement is correct. Zn2+ is formed when zinc loses two electrons and gets oxidized to Zn2+.