Question

A car started to move ftom the rest and covers 2 km distance producing an acceleration of 0.5m/s2 find its velocity how long time does it take to cover the distance of 1.6km

Answer 1

(a) 44.7 m/s

We can find the final velocity of the car by using the SUVAT equation:

`v^2-u^2 = 2ad`

where

v is the final velocity

u = 0 is the initial velocity (the car starts from rest)

`a=0.5 m/s^2` is the acceleration

`d=2km = 2000 m` is the displacement

Solving for v,

`v=√(u^2 +2ad)=√(0+2(0.5)(2000))=44.7 m/s`

(b) 80 s

We can find the time it takes for the car to cover 1.6 km by using the following SUVAT equation:

`d=ut+(1)/(2)at^2`

where in this case we have

d = 1.6 km = 1600 m is the displacement

`a=0.5 m/s^2` is the acceleration

u = 0

t is the time

Solving for t, we find:

`t=\sqrt{(2d)/(a)}=\sqrt{(2(1600))/(0.5)}=80 s`