Answer:
(a) 0.84 s
(b) 8.22 m/s
(c) 15.33 m/s
Step-by-step explanation:
u = 0 , h = 3.45 m, g = 9.8 m/s^2
Let time taken to reach the water is t and the velocity at the time of hitting of water surface is v.
(a) Use first equation of motion
s = u t + 1/2 a t^2
3.45 = 0 + 0.5 x 9.8 x t^2
t = 0.84 second
(b) Use first equation of motion
v = u + a t
v = 0 + 9.8 x 0.84 = 8.22 m/s
(c) If h = 12 m
use third equation of motion
v^2 = u^2 + 2 g h
v^2 = 0 + 2 x 9.8 x 12
v = 15.33 m / s