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An automobile tire has a radius of 0.344 m, and its center moves forward with a linear speed of v = 20.1 m/s. (a) Determine the angular speed of the wheel. (b) Relative to the axle, what is the tangential speed of a point located 0.135 m from the axle?

User Katelynn
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1 Answer

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Answer:

The angular speed and tangential speed are 58.69 rad/s and 7.92 m/s.

Step-by-step explanation:

Given that,

Radius = 0.344 m

Speed v= 20.1 m/s

(I). We need to calculate the angular speed

Firstly we will calculate the time

Using formula of time


t = (d)/(v)


t=(2\pi* r)/(v)


t =(2*3.14*0.344)/(20.1)


t=0.107

The angular velocity of the tire


\omega=(2\pi)/(t)


\omega=(2*3.14)/(0.107)


\omega=58.69\ rad/s

Now, using formula of angular velocity

(II). We need to calculate the tangential speed of a point located 0.135 m from the axle

The tangential speed


v = r\omega

Where,

r = distance


\omega= angular velocity

Put the value into the formula


v= 0.135*58.69


v=7.92\ m/s

Hence, The angular speed and tangential speed are 58.69 rad/s and 7.92 m/s.

User Arcadian
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