Answer : The final volume of oxygen gas will be, 1.292 ml
Explanation :
Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
![V\propto T](https://img.qammunity.org/2020/formulas/chemistry/high-school/ex52vv3nyvdiyg3q5bspxziz008p7ttnt3.png)
or,
![(V_1)/(V_2)=(T_1)/(T_2)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/1i2amfza8x9zc8ilyu83k74ofhqlqvi93w.png)
where,
= initial volume of oxygen gas = 1.75 ml
= final volume of oxygen gas = ?
= initial temperature of gas =
![97.8^oC=273+97.8=370.8K](https://img.qammunity.org/2020/formulas/chemistry/college/32mtchtojhrjiaj1498ybwux688l5m9bry.png)
= final temperature of gas =
![0.7^oC=273+0.7=273.7K](https://img.qammunity.org/2020/formulas/chemistry/college/fycpjdo4rcl97oaehud198dthstycjdh4r.png)
Now put all the given values in the above formula, we get the final volume of the oxygen gas.
![(1.75ml)/(V_2)=(370.8K)/(273.7K)](https://img.qammunity.org/2020/formulas/chemistry/college/3eco0y5ummeywq5jy4m8xqer7ni86ihaya.png)
![V_2=1.292ml](https://img.qammunity.org/2020/formulas/chemistry/college/gjpefgyziogb6659vf0jx67ctom3yvzleg.png)
Therefore, the final volume of oxygen gas will be, 1.292 ml