Answer:
![y-6=-(5)/(4)(x+2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j7ube9wi9twiy7lpt1i1g6oylokuw5nzl8.png)
![y-1=-(5)/(4)(x-2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xrpjcq4clb7wga7b2rrvo6m7mrmlgteq6q.png)
![y-3.5=-1.25x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5b2rod4fhdelkijvagko8fhbc5jtkyu6ev.png)
Explanation:
step 1
Find the slope of the linear equation
with the points (-2,6) and (2,1)
The formula to calculate the slope between two points is equal to
substitute
step 2
Find the equation of the line into point slope form
The equation of the line in slope point form is equal to
![y-y1=m(x-x1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/38rsw060gekfjbf76g57jsb45ginj88wcy.png)
we have
1) with the point (-2,6)
substitute
![y-6=-(5)/(4)(x+2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j7ube9wi9twiy7lpt1i1g6oylokuw5nzl8.png)
2) with the point (2,1)
substitute
![y-1=-(5)/(4)(x-2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xrpjcq4clb7wga7b2rrvo6m7mrmlgteq6q.png)
3) with the point (0,3.5)
substitute
![y-3.5=-(5)/(4)(x-0)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vxjvxy1ucxs86s9v6ean0u38qfpfysz379.png)
------->
![y-3.5=-1.25x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5b2rod4fhdelkijvagko8fhbc5jtkyu6ev.png)