Question

Which points are a distance of 5 units from (2, 3) if ? (7, 3) (–1, –1) (0, 3) (2, 8) (−7, 6)

Answer 1

Explanation:

The correct answer are A B and D

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Answer 2

(7, 3), (–1, –1) and (2, 8) are at a distance of units from (2, 3).

Explanation:

We know that the formula of distance is given by:

Distance =
`√((x_2-x_1)^2+(y_2-y_1)^2)`

So substituting the given points points to check which points are at a distance of 5 units from
`(2,3)`.

1. (2, 3) and (7, 3):

`√((7-2)^2+(3-3)^2) =√(25) = 5`

2. (2, 3) and (–1, –1):

`√((-1-2)^2+(-1-3)^2) =√(25) = 5`

3. (2, 3) and (0, 3):

`√((0-2)^2+(3-3)^2) =√(4) = 2`

4. (2, 3) and (2, 8):

`√((2-2)^2+(8-3)^2) =√(25) = 5`

5. (2, 3) and (-7, 6):

`√((-7-2)^2+(6-3)^2) =√(90) =9.5`