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You need 480 mL of a 50% alcohol solution. On hand, you have a 40% alcohol mixture. How much of the 40% alcohol mixture and pure alcohol will you need to obtain the desired solution?

You will need
____ mL of the 40% solution
and
____ mL of pure alcohol

User Enkows
by
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1 Answer

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Explanation:

x+40%x=50%×480ml

x being 100% alcohol

14x=240ml

x=120/7 ml

x=17.(142857) ml

User Yoah
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