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What is the x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5?
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2 votes
What is the x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5?

User Kristof Jozsa
by
5.3k points

2 Answers

3 votes

Answer:

x= -2

Explanation:

-b/2a = x

-(12)/2(2) = x

-12/6 = x

-2 = x

User Conffusion
by
5.8k points
5 votes

Answer:

(-2,-7)

Explanation:

User Lissie
by
5.2k points
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