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Select the correct answer from the drop-down menu.

Consider the equations y=√x and y=x² -1
The system of equations is equal at approximately
A.(1.5,1.2)
B.(-1.5,-1.2)
C.(1.5,-1.2)
D.(-1.5,1.2)

User Pugna
by
6.5k points

2 Answers

2 votes

Answer:

Choice A.

Step.-by-step explanation:

y=√x

y=x² -1

Substituting the values in choice A:

1.2 = √1.5 = 1.2247 Approximately equal.

1.2 = (1.5)^2 - 1 = 1.25 Approximately equal.

Choice B.

-1.2 = √-1.5 which is imaginary so NOT this one.

Choice C

-1.2 = √1.5 = -1.2247

-1.2 = (1.5)^2 - 1 = 1.25 NO.

Choice D

We have the non real value √-1.5 again so NOT this one.

User Cro
by
6.3k points
2 votes

Answer: Option A

A.(1.5,1.2)

Explanation:

We have the following system of equations


y=√(x)


y=x^2 -1

the solution of the system will be all points that satisfy both equations at the same time

For (1.5,1.2)


y=√(1.5)=1.2


y=(1.5)^2 -1=1.2

Both equations are satisfied

Note that we can discard options B and D because the domain of the equation
y =√(x) does not include the negative numbers.

We can discard option C because the range of the function
y =√(x) does not include the negative numbers.

Finally the answer is the option A

User Jpo
by
6.0k points