Question

Resistors R1, R2, and R3 are connected in parallel. R1 is 68 ohm and R2 is 93 ohm. The equivalent resistance of the parallel combination is 26-ohm. What is the resistance of R3?

please show work! :)

Answer 1

77 Ω

Step-by-step explanation:

For resistors in parallel:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/26 = 1/68 + 1/93 + 1/R₃

1/R₃ = 0.013

R₃ = 77

The resistance of R₃ is 77 Ω.

Answer 2

R3=76.9 ohm

Step-by-step explanation:

Hello

the equivalent resistance is given by the expression:

`(1)/(R_(eq) ) =(1)/(R_(1) ) +(1)/(R_(2) )+(1)/(R_(3) )+...(1)/(R_(n) )`

we have R1=68 ohm, R=93 ohm, Rt=26 and the resistor R3 is unknown.

`(1)/(26 ) =(1)/(68 ) +(1)/(93) }+(1)/(R_(3) )\\(1)/(26 ) =(((93*R_(3))+(68*R_(3))+(68*93)) )/(68*93*R_(3) )\\26((93*R_(3))+(68*R_(3))+(68*93)) }={68*93*R_(3) }\\\\\\2418R_(3)+1768R_(3)+164424=6324R_(3)\\R_(3)(2418+1768-6324)=164424\\-2138R_(3)=-164424\\R_(3)=(164424)/(2138)\\ R_(3)=76.9 ohm`

Have a great day.