Question

2.00 L of nitrogen gas at a temperature of 210 K are cooled down until the new volume is 1.25 L. If the pressure and number of gas particles do not change, to what temperature was the gas cooled?

131 K

1.19 x 10-2 K

7.62 x 10-3 K

336 K

Please answer ASAP!!

Answer 1

131 K

Step-by-step explanation:

The only variables are volume and temperature, so we can use Charles' Law:

V1/T1 = V2/T2

Data:

V1 = 2.00 L; T1 = 210 K

V2 = 1.25 L; T2 = ?

Calculation:

2.00/210 = 1.25/T2

Multiply each side by the lowest common denominator (210T2)

2.00T2 = 1.25 ×210

2.00T2 = 262.5

T2 = 262.5/2.00 = 131 K

The gas was cooled to 131 K.