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3 votes
Lim-0
(1 + 3x)/x =?????​

User Mettleap
by
7.9k points

2 Answers

3 votes

Answer:

See below.

Explanation:

The two sided limit does not exist.

As x approaches 0 from negative values the limit is -∞.

As x approaches 0 from positive values the limit is ∞.

User JSantos
by
8.7k points
2 votes

Answer:

not exist

Explanation:


\lim\limits_(x\to0)(1+3x)/(x)\\\\\lim\limits_(x\to0^+)(1+3x)/(x)=(1+(3)(0))/((+))=(1)/((+))=+\infty\\\\\lim\limits_(x\to0^-)(1+3x)/(x)=(1+(3)(0))/((-))=(1)/((-))=-\infty

User Joe Simpson
by
9.2k points

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