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If Tucson's average rainfall is 12 3/4 inches and Yuma's is 3 4/5. How much more rain, on the average, does Tucson get than Yuma?

User JakubRi
by
7.5k points

2 Answers

1 vote

Answer:


8(19)/(20) in.

Explanation:

To find your answer, subtract.


12(3)/(4) may be rewritten as
(51)/(4) and
3(4)/(5) may be rewritten as
(19)/(5)

Establish a common denominator, which would be the lowest common multiple of 4 and 5, which is 20. Multiply both parts of your first fraction by 5 to get a denominator of 20, and both parts of your second fraction by 4 to get a denominator of 20.


(51)/(4) *(5)/(5) =(255)/(20)

and


(19)/(5) *(4)/(4) =(76)/(20)

Subtract.


(255)/(20) -(76)/(20) =(179)/(20)

This fraction may be rewritten as
8(19)/(20).

User Edwyn
by
8.9k points
3 votes

Answer:


8(19)/(20) inches.

Explanation:

Average rainfall of Tucson =
12(3)/(4) inches

or
(51)/(4) inches

Average rainfall of Yuma = [tex3\frac{4}{5}[/tex] inches

or
(19)/(5) inches

Now we have to find the fifference of average rainfall in Tucson as compared to Yuma.

Difference =
(51)/(4) -
(19)/(5)

=
(255-76)/(20)

=
(179)/(20)

=
8(19)/(20) inches.

User Kmm
by
7.9k points