Question

MAJOR HELPPPP!!!!

An earthquake registered 7.4 on the Richter scale. If the reference intensity of this quake was 2.0 × 10^11, what was its intensity?

Answer 1

5.02×10^18

I got it right.

Answer 2

The correct answer would be: C. 5.02 x 10^18

Here's how you solve it!

Since the earthquake registered is 7.4 on the scale let it represent RS=7.4

The reference intensity is 2.0 x 10^11 so let it represent RI= 2.0 x 10^11

Now you need to use the formula.

`RS=log((I)/(I_(r) ) )`

Then we need to plug in the values for the formula

`7.4=log((I)/(2.0 x 10^(11) ) )`

`I=10^(7.4)` x
`2.0` x
`10^(11)`

`I= 5.02` x
`10^(18)`

Hope this helps! :3