Question

The decomposition of N2O5 can be described by the equation.

2N2O5 (soln) ---> 4NO2 (soln) + 2 (g)

Given this data for the reaction at 45 degrees C in carbon tetrachloride solution, calculate the average rate for each successive time interval.

t(s) [N2O5] (M)


0 2.10

195 1.86

556 1.48

825 1.25

Interval: 0 s to 195 s

Reaction rate= _____M/s

195 s to 556 s

Reaction rate= _____M/s

556 s to 825 s

Reaction rate= _____M/s

Answer 1

1) Reaction rate= 0.001230 M/s

2) Reaction rate= 0.001052 M/s

3) Reaction rate=0.000855 M/s

Step-by-step explanation:

Average Rate of the reaction is defined as rate at any instant of time is the rate of change in concentration of any one of the reactants or products with respect to particular time.It is given as;

`r_a=-(x_2-x_1)/(t_2-t_1)`

`x_2,x_1` : concentration at time
`t_1\&t_2` respectively.

`2N_2O_5 (soln)\rightarrow 4NO_2 (soln) + 2O_2 (g)`

1) Interval: 0 s to 195 s

`t_1=0s,t-2=195 s`

`x_1=2.10 M,x_2=1.86 M`

`r_a=-(1.86 M-2.10 M)/(195 s-0 s)=0.001230 M/s`

2) Interval: 195 s to 556 s

`t_1=195s,t-2=556 s`

`x_1=1.86 M,x_2=1.48 M`

`r_a=-(1.48 M-1.86 M)/(556 s-195 s)=0.001052 M/s`

3) Interval: 556 s to 825 s

`t_1=556 s,t_2=825`

`x_1=1.48 M,x_2=1.25M`

`r_a=-(1.25M-1.48 M)/(825s-556 s)=0.000855 M/s`