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3 votes
Write 1-2log7x as a single logarithm

1 Answer

5 votes

Answer:


log_(7) (7)/(x^(2) )

Explanation:

We need to write
1 - 2log_(7)x as a single logarithm.

We know that


log_(7)7 = 1

Therefore we have:


log_(7)7 - 2log_(7)x


log_(7)7 - log_(7)x^(2)


log_(7) (7)/(x^(2) )

The solution is:
log_(7) (7)/(x^(2) )

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