Question

Graph the line with slope -2/3 passing through the point (-3,5)​

Answer 1

`\large\boxed{y-5=-(2)/(3)(x+3)}`

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point on a line

We have the slope
`m=-(2)/(3)` and the point
`(-3,\ 5)`.

Substitute:

`y-5=-(2)/(3)(x-(-3))\\\\y-5=-(2)/(3)(x+3)`