Answer:
![142.58\text{squared kg}[](https://img.qammunity.org/2020/formulas/mathematics/college/y1547wnq0oyjxgrz6a1l82gzk7wfq6bc34.png)
Explanation:
Answer:
Explanation:
Given : A random sample of 10 subjects have weights with a standard deviation of 11.9407 kg
i.e.
![\sigma = 11.9407](https://img.qammunity.org/2020/formulas/mathematics/college/ivw7sv9hcbnztrowbc7o5zydprg4kl9sh0.png)
Since we know that the value of variance is the square of standard deviation.
i.e.
![\text{Variance}=\sigma^2](https://img.qammunity.org/2020/formulas/mathematics/college/mnubtl3q65nxg76zrkxwhqz599lyqs3h5h.png)
Therefore, to find the value of variance, we need to find the square of the given standard deviation.
i.e.
![\text{Variance}=(11.9407)^2=142.58031649\approx142.58\text{squared kg}](https://img.qammunity.org/2020/formulas/mathematics/college/kzc7y5y11hbphumrzot6brddb0i8qkl6zd.png)
Thus, the variance of their weights =
![142.58\text{squared kg}[](https://img.qammunity.org/2020/formulas/mathematics/college/y1547wnq0oyjxgrz6a1l82gzk7wfq6bc34.png)