Answer:
The answer in the procedure
Explanation:
we know that
The volume of a rectangular pyramid is equal to
![V=(1)/(3)LWH](https://img.qammunity.org/2020/formulas/mathematics/high-school/p89caluvzbyv3oyrzef7clghtoeqnmai72.png)
where
L is the length of the rectangular base
W is the width of the rectangular base
H is the height of the pyramid
If the pyramid is scaled proportionally by a factor of k
then
the new dimensions are
L=kL
W=kW
H=kH
substitute and find the new Volume V'
![V'=(1)/(3)(kL)(kW)(kH)](https://img.qammunity.org/2020/formulas/mathematics/high-school/v6il5o3ha8qehhvhx3hzcc7va3ljdku2nc.png)
![V'=(1)/(3)(k^(3))LWH](https://img.qammunity.org/2020/formulas/mathematics/high-school/s4m68bhd9exg1p95q1rou7tefuoyarhh83.png)
![V'=(k^(3))(1)/(3)LWH](https://img.qammunity.org/2020/formulas/mathematics/high-school/flbii3h1bxog8mqqkwbslxdtvq2ro3g9r3.png)
![V'=(k^(3))V](https://img.qammunity.org/2020/formulas/mathematics/high-school/xf9hlvd0624sw6t7ll8a2176nqyh59202w.png)
The new volume is equal to the scale factor k elevated to the cube multiplied by the original volume