Question

A proton is propelled at 4×106 m/s perpendicular to a uniform magnetic field. 1) If it experiences a magnetic force of 4.8×10−13 N, what is the strength of the magnetic field? (Express your answer using two significant figures.)

Answer 1

B = 0.75 T

Step-by-step explanation:

As we know that the force on a moving charge in magnetic field is given by the formula

`F = qvB`

here we have

`B = (F)/(qv)`

here we know that

`F = 4.8 * 10^(-13) N`

`q = 1.6 * 10^(-19) C`

`v = 4 * 10^6 m/s`

now from above equation we have

`B = (4.8 * 10^(-13))/((1.6 * 10^(-19))(4 * 10^6))`

`B = 0.75 T`