Answer:
![(3)/(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kg5hqzgl559htm091adak006z3lpj0xp6q.png)
Explanation:
Let A be the event of getting a factor of 15 when a fair spinner numbered 1 - 5 spins and B be the event that a fair coin is tossed.
The factors of 15 =
![1,\ 3,\ 5](https://img.qammunity.org/2020/formulas/mathematics/high-school/6171f0den8rh2peko2ysepreinxremo5d5.png)
Then ,the probability of obtaining a factor of 15 is given by :-
![P(A)=(3)/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/o8voqcs9xc1jn4afllhyl1iqivcfvdkn9o.png)
The probability of getting a tail :-
![P(B)=(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/q4ojhekingexku2z2e4satug03b87c69wx.png)
Since both the events are independent , thus
The probability of obtaining a factor of 15 and a tail is given by :-
![P(A)* P(B)\\\\=(3)/(5)*(1)/(2)=(3)/(10)](https://img.qammunity.org/2020/formulas/mathematics/high-school/cxkwicqujlxtyu805o0ryq2get651bcnxw.png)
Hence, the required probability :
![(3)/(10)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kg5hqzgl559htm091adak006z3lpj0xp6q.png)