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The vertex form of the equation of a parabola is y=6(x-2)2-8. What is the standard form of the equation?

The vertex form of the equation of a parabola is y=6(x-2)2-8. What is the standard-example-1
User Nan
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2 Answers

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The answer is D!!!

y=6x^2-24x+16

User Ben Trewern
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Answer:

Option 4 -
y=6x^2-24x+16

Explanation:

Given : The vertex form of the equation of a parabola is
y=6(x-2)^2-8

To find : What is the standard form of the equation?

Solution :

The vertex form of the equation of a parabola is
y=6(x-2)^2-8

We solve the equation to get standard form,


y=6(x^2-2^2-2(x)(2))-8


y=6(x^2+4-4x)-8


y=6x^2+24-24x-8


y=6x^2-24x+16

The standard form of the equation is
y=6x^2-24x+16

Therefore, Option 4 is correct.