Question

A. y-2=2(x-3)
B. y-3=2(x-2)
C. y-10=2(x-1)
D. y-1=2(x-10)

Answer 1

C. y - 10 = 2(x - 1)

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have the points (-3, 2) and (1, 10). Substitute:

`m=(10-2)/(1-(-3))=(8)/(4)=2`

Using the point (-3, 2):

`y-2=2(x-(-3))\\\\y-2=2(x+3)`

Using the point (1, 10):

`y-10=2(x-1)`

Answer 2

C. y-10=2(x-1)

Explanation:

We have two points on the line, we can find the slope

m = (y2-y1)/(x2-x1)

= (10-2)/(1--3)

= 8/(1+3)

=8/4

=2

The slope is 2

We can use point slope form using the point (1,10)

y-y1 = m(x-x1)

y-10 = 2(x-1)