Question

Distance between coordinates -10, -
9 and 6,8​

Answer 1

`\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-10}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ d=√([6-(-10)]^2+[8-(-9)]^2)\implies d=√((6+10)^2+(8+9)^2) \\\\\\ d=√(256+289)\implies d=√(545)\implies d\approx 23.35`

Answer 2

sqrt(545)

Explanation:

The distance between 2 points can be found by

d = sqrt( (x2-x1)^2 + (y2-y1)^2)

= sqrt( (6--10)^2 + (8--9)^2)

sqrt( (6+10)^2 + (8+9)^2)

sqrt( (16)^2 + (17)^2)

sqrt( 256+289)

sqrt(545)