Question

A go cart rolling at a speed of 2 m/s begins to accelerate down an inclined street at a constant rate of 1.5 m/s¶. It takes the go cart 6 seconds to reach a level portion of the street. At what speed will the cart be traveling by the time it reaches level ground.

Answer 1

`11(m)/(s)`

Step-by-step explanation:

As per the Newton's first law of motion,

`v = u + at\\`

where "v" is the final speed

"u" is the initial speed

"a" is the acceleration

and "t" is the time taken

Substituting the given values in above equation, we get -

`v = 2 + (1.5)*6\\= 2 + 9\\= 11`
`(m)/(s)\\`

The cart be traveling at a speed of
`11 (m)/(s)` by the time it reaches level ground.