33.2k views
4 votes
How to solve 3,4 and 6

How to solve 3,4 and 6-example-1
User Thriqon
by
7.1k points

1 Answer

4 votes

Answer:


\large\boxed{3.\ V\approx130.88\ m^3}\\\boxed{4.\ V\approx35.21}\\\boxed{6.\ V\approx1.06\ in^3}

Explanation:

3.

The formula of a volume of a sphere:


V=(4)/(3)\pi R^3

R - radius

We have R = 3.15 m. Substitute:


V=(4)/(3)\pi(3.15)^3\approx(4)/(3)\pi(31.26)\approx(4)/(3)(3.14)(31.26)\approx130.88\ m^3

4.

The formula of a volume of a cone:


V=(1)/(3)\pi r^2H

r - radius

H - height

We have 2r = 11.6 → r = 5.8 and H = x. Substitute:


V=(1)/(3)\pi(5.8)^2(x)=(1)/(3)\pi(33.64)x\approx(1)/(3)(3.14)(33.64)x\approx35.21

6.

The formula of a volume of a cube:


V=s^3

s - edge

We have s = 1.02 in. Substitute:


V=(1.02)^3\approx1.06\ in^3

User Lookbadgers
by
7.3k points