Answer : The absolute permeability is, 0.111 darcys.
Explanation : Given,
Volumetric constant rate =
![0.5cm^3/s](https://img.qammunity.org/2020/formulas/chemistry/college/8yjaqbet729p6gw72600efs5p8dp4sb4nw.png)
Cross section area =
![3cm^2](https://img.qammunity.org/2020/formulas/chemistry/college/t11z7tggqowmjnbjpign5lvhbl37dao2zt.png)
Pressure = 2 atm
Viscosity = 1.0 cp
Length of rock = 4 cm
From the Darcy equation we conclude that,
![\text{Volumetric constant rate}=\frac{(\text{Absolute permeability}* A* P)}{\eta * l}](https://img.qammunity.org/2020/formulas/chemistry/college/2ejs83g7it67lwt9k45sir8xiobk7nul3a.png)
where,
A = cross section area
P = pressure
= viscosity
l = length of rock
Now put all the given values in the above formula, we get:
![0.5cm^3/s=\frac{(\text{Absolute permeability}* 3cm^2* 2\text{ atm})}{1.0cp * 4cm}](https://img.qammunity.org/2020/formulas/chemistry/college/3fvttc175kzanm873zssvjvrrbbb2dcl5n.png)
![\text{Absolute permeability}=0.111\text{ darcys}](https://img.qammunity.org/2020/formulas/chemistry/college/ob6rffq9qui5xbgyh6qdal6v1eprfkk1y6.png)
Therefore, the absolute permeability is, 0.111 darcys.