Question

Now let M react, and at time = 0, [M] = 0.102 M, A(545nm) = 0.491; at time = 30 seconds, A(545nm) = 0.404. What is the [M] at 30 seconds? What is the slope of the Absorbance vs. [M] function? What is the (average) rate of the reaction during this time period.

If a new reaction was run leaving [N] the same, but beginning (time = 0) with [M] = 0.204 M, A(545nm) = 0.981. After 30 seconds, A (545 nm) is 0.807. What is the order of the reaction with respect to [M] ?

Answer 1

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Step-by-step explanation:

`\geqslant { \sqrt[ \geqslant \sqrt[ \geqslant \leqslant \sqrt[ \geqslant ]{0.time} * ( log_(30.0m)(3.71m) )/(204.9m) ]{3528t} ]{3} }^(8) * (4)/(3)`