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A bag of 29 tulip bulbs contains 10 red tulip​ bulbs, 10 yellow tulip​ bulbs, and 9 purple tulip bulbs. ​(a) What is the probability that two randomly selected tulip bulbs are both​ red? ​(b) What is the probability that the first bulb selected is red and the second​ yellow? ​(c) What is the probability that the first bulb selected is yellow and the second​ red? ​(d) What is the probability that one bulb is red and the other​ yellow?

1 Answer

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Answer:

a.The probability that two randomly selected tulip bulbs both are red=
(45)/(406).

b.The probability that the first bulb selected is red and second yellow=
(50)/(406).

c.The probability that the first bulb selected is yellow and the second red=
(50)/(406).

d.The probability that one bulb is red and other yellow=
(50)/(203).

Explanation:

Given

Total number of bulbs= 29

Number of bulbs of red=10

Number of yellow bulbs=10

Number of purple bulbs=9

Formula of probability, P(E)=
(favourable \; cases)/(total\;number\; of \; cases)

a.The probability that two randomly selected tulip bulbs are both red=
(10)/(29)*(9)/(28)=(45)/(406).

b.The probability of getting first bulb is red=
(10)/(29).

The probability of getting second bulb is yellow=
(10)/(28)

Hence,the probability that the firs bulb selected is red and the second bulb yellow=
(10)/(29)*(9)/(28)=(45)/(406)

c. The probability of getting firs bulb is yellow =
(10)/(29)

The probability of getting second bulb is red=
(10)/(28)

Hence,the probability that the firs bulb selected is yellow and the second bulb red=
(10)/(29)*(10)/(28)=(50)/(406).

d.The probability of getting first bulb is red and second is yellow=
(50)/(406)

The probability of getting first bulb is yellow and second is red=
(50)/(406)

The probability that one bulbe is red and other is yellow= probability of getting first bulb is red and other yellow+ probability of getting first bulb is yellow and other is red

Hence, the probability of getting one bulb is red and other is yellow=
(50)/(406)+(50)/(406)=(50)/(203)

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