R = 899.985Ω.
The ammeter gives a lecture of I = 0.13A through the resistor and the voltmeter gives a lecture of V = 117V between the points a and c, the ammeter resistance is Ra = 0.015Ω. So, the voltmeter reading is the sum of the potential difference Vbc (through the ammeter) and Vab (through the resistor).
To obtain the voltage Vbc through the ammeter from its known current and resistance, Ohm's law is used.
Vbc = I*Ra = (0.13A)(0.015Ω) = 0.00195V
Vab = V - Vbc = 117V - 0.00195V = 116.99805V
We know that Vab = I*R. Clear R from the equation:
R = Vab/I = 116.99805V/0.13A = 899.985Ω