Question

Two point charges Q1 = +5.70 nC and Q2 = −2.30 nC are separated by 45.0 cm. (a) What is the electric potential at a point midway between the charges? 111.3 Incorrect: Your answer is incorrect. seenKey 136 U

Answer 1

Step-by-step explanation:

It is given that,

Charge,
`Q_1=5.7\ nC=5.7* 10^(-9)\ C`

Charge,
`Q_2=-2.3\ nC=-2.3* 10^(-9)\ C`

Distance between charges, d = 45 cm = 0.45 m

We need to find the electric potential at a point midway between the charges. It is given by :

`V=(kQ_1)/(r_1)+(kQ_2)/(r_2)`

`V=k((Q_1)/(r_1)+(Q_2)/(r_2))`

Midway between the charges means, r = 22.5 cm = 0.225 m

`V=9* 10^9* ((5.7* 10^(-9)\ C)/(0.225\ m)+(-2.3* 10^(-9)\ C)/(0.225\ m))`

`V=136\ volts`

So, the electric potential at a point midway between the charges is 136 volts. Hence, this is the required solution.