Question

A reaction in which the rate depends linearly only on one reactant concentration is called ​

Answer 1

That's called a first-order reaction.

Step-by-step explanation:

In kinematics, the order of a chemical reaction is the sum of the power of concentrations in is rate law.

For example, consider a reaction with the following rate law:

`\text{Rate} = k\cdot [\mathrm{A}]^(a)\cdot [\mathrm{B}]^(b)`,

where
`[\mathrm{A}]` and
`[\mathrm{B}]` are the concentrations of the two reactants,
`\mathrm{A}` and
`\mathrm{B}`.

The order of this reaction will be equal to the sum of the powers of the concentrations in the rate law. For this sample reaction, the order is equal to
`a + b`.

For the reaction in this question, the rate law will resemble the following:

`\text{Rate} = k\cdot [\mathrm{A}]`.

Note that the power "
`1`" next to the concentration of
`\mathrm{A}` is omitted. The order of this reaction will be numerically equal to one.

However, by convention, the order of the reaction is named in ordinals. (That is: first, second, third, etc.) The reaction here is known as a first-order reaction.

(Reference: "The Rate Law", Physical & Theoretical Chemistry, Chemistry Libretexts; "Cardinal and Ordinal Numbers Chart", Math Is Fun)