Question

He function f(x) = x^2 + 10x - 3 written in vertex form is fx) = (x+5)^2– 28. What are the coordinates of the vertex?

0 (-5, -28)
O (-5, 28)
O (5.-28)
O (5, 28)

Answer 1

(- 5, - 28 )

Explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

f(x) = (x + 5)² - 28 ← is in vertex form

with vertex (h, k) = (- 5, - 28)