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What are the zeros of the function?
f(x)=x^2+7x-60

2 Answers

4 votes

Answer:

(-12, 0) and (5, 0)

Explanation:

f(x) = x² + 7x − 60

Here, a = 1, b = 7, c = -60. Using the AC method, we need to find factors of a×c that add up to b.

12 × -5 = -60

12 + -5 = 7

The factors are 12 and -5.

f(x) = (x + 12) (x − 5)

The zeros are:

x + 12 = 0, x − 5 = 0

x = -12, x = 5

The zeros are (-12, 0) and (5, 0).

User Pavel Strakhov
by
7.0k points
3 votes


x^2+7x-60 =0\\x^2-5x+12x-60=0\\x(x-5)+12(x-5)=0\\(x+12)(x-5)=0\\x=-12 \vee x=5

User TechnoTarek
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7.1k points