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A solid iron cylinder weighs 600 N. It has a density of 7860 kg/m^3. (a) Calculate the cylinder's volume. (b) How much would the cylinder weigh if it is completely submerged in water?
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A solid iron cylinder weighs 600 N. It has a density of 7860 kg/m^3. (a) Calculate the cylinder's volume. (b) How much would the cylinder weigh if it is completely submerged in water?

User Jamesc
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2 votes

Answer:

7.66 (litres); 523.66 (N).

Step-by-step explanation:

all the details are provided in the attached picture. Note, P_i means 'Weight of iron', ρ_i means "Density of iron', ρ_w means 'Density of water', F_f means 'Arhimede force'.

The answers are marked with red colour.

A solid iron cylinder weighs 600 N. It has a density of 7860 kg/m^3. (a) Calculate-example-1
User Dileep Reghu
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