Question

A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity is 9.8 m/s 2 . 2 What is the gravitational potential energy associated with the ball relative to the ceiling? Answer in units of J. 012 (part 2 of 3) What is its gravitational potential energy relative to the floor? Answer in units of J. 013 (part 3 of 3) What is its gravitational potential energy relative to a point at the same elevation as the ball? Answer in units of J.

Answer 1

1. -23.2 J

The gravitational potential energy of the ball is given by

`U=mgh`

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

`U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J`

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

`U=mgh`

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

`U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J`

3. 0 J

As before, the gravitational potential energy of the ball is given by

`U=mgh`

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

`U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J`