Question

A place kicker applies an average force of 2400 N to a football of .040 kg. The force is applied at an angle of 20.0 degrees from the horizontal. Contact time is .010 sec. a. Find the velocity of the ball upon leaving the foot. b. Assuming no air resistance find the time to reach the goal posts 40.0 m away. c. The posts are 4.00 m high. Is the kick good? By how much?

Answer 1

a) The velocity of the ball upon leaving the foot = 600 m/s

b) Time to reach the goal posts 40.0 m away = 0.07 seconds

c) The kick won't e going inside goal post, it is higher by 10.34m.

Step-by-step explanation:

a) Rate of change of momentum = Force

`\frac{\texttt{Final momentum - Initial momentum}}{\texttt{Time}}=\texttt{Force}\\\\(0.040v-0.040* 0)/(0.010)=2400\\\\v=600m/s`

The velocity of the ball upon leaving the foot = 600 m/s

b) Horizontal velocity = 600 cos20 = 563.82 m/s

Horizontal displacement = 40 m

Time

`t=(40)/(563.82)=0.07s`

Time to reach the goal posts 40.0 m away = 0.07 seconds

c) Vertical velocity = 600 sin20 = 205.21 m/s

Time to reach the goal posts 40.0 m away = 0.07 seconds

Acceleration = -9.81m/s²

Substituting in s = ut + 0.5at²

s = 205.21 x 0.07 - 0.5 x 9.81 x 0.07²= 14.34 m

Height of ball = 14.34 m

Height of post = 4 m

Difference in height = 14.34 - 4 = 10.34 m

The kick won't e going inside goal post, it is higher by 10.34m.