Answer:
Capacitance of the capacitor = 0.547 F
Step-by-step explanation:
We charge of capacitor,
Q = CV
Let Q be the initial charge,we have voltage = 84 V
Q = C x 84 = 84 C
We have final charge = Q + 20.25 and voltage = 121 V
Q + 20.25 = 121 C
Substituting Q value from previous equation
84 C + 20.25 = 121 C
37 C = 20.25
C = 0.547 F
Capacitance of the capacitor = 0.547 F