Question

A balloon having an initial temperature of 17.8°C is heated so that the volume doubles while the pressure is kept fixed. What is the new value of the temperature?

Answer 1

`T = 308.6 ^0 C`

Step-by-step explanation:

Here by ideal gas equation we can say

`PV = nRT`

now we know that pressure is kept constant here

so we will have

`V = (nR)/(P) T`

since we know that number of moles and pressure is constant here

so we have

`(V_2)/(V_1) = (T_2)/(T_1)`

now we know that initial temperature is 17.8 degree C

and finally volume is doubled

So we have

`(2V)/(V) = (T_2)/((273 + 17.8))`

so final temperature will be

`T_2 = 581.6 k`

`T_2 = 308.6 ^o C`