Answer:
Original speed of the bullet = 305.21 m/s
Step-by-step explanation:
Here momentum is conserved.
Mass of bullet = 9.6 g = 0.0096 kg
Mass of wood = 4.95 kg
Let velocity of bullet be v.
Initial momentum = 0.0096 v
Final mass = 0.0096 + 4.95 = 4.9596 kg
Final velocity = 0.591 m/s
Final momentum = 4.9596 x 0.591 = 2.93 kgm/s
Equating both momentum
0.0096 v = 2.93
v = 305.21 m/s
Original speed of the bullet = 305.21 m/s