Question

A turntable rotates counterclockwise at 76 rpm . A speck of dust on the turntable is at 0.45 rad at t=0. What is the angle of the speck at t = 8.0 s ? Your answer should be between 0 and 2Ï rad.

Answer 1

64.08 rad

Step-by-step explanation:

f = 78 rpm = 76 / 60 rps

θ = 0.45 rad, t = 8 s

(θ2 - θ1) / t = ω

θ2 - θ1 = 2 x 3.14 x 76 x 8 / 60 = 63.63

Angle turns from initial position = 0.45 + 63.63 = 64.08 rad