Question

A motorcycle rider executes a loop-to-loop stunt in a loop with a diameter of 8.4 m At the top of the loop, the rider has a speed of 7.5 m/s. The combined mass of the rider and motorcycle is 175 kg. Determine the normal force between the motorcycle and track at the top of the loop

Answer 1

The normal force between the motorcycle and track at the top of the loop = 2343.75 N

Step-by-step explanation:

At the top of the loop the track is directed tangential to the motion, the normal to the tangent is along radius of circle. that is here we need to find centripetal force.

We have expression for centripetal force

`F=(mv^2)/(r)`

Here mass, m = 175 kg

Velocity, v = 7.5 m/s

Diameter, d = 8.4 m

Radius, r = 0.5d = 0.5 x 8.4 = 4.2 m

Substituting

`F=(mv^2)/(r)=(175* 7.5^2)/(4.2)=2343.75N`

The normal force between the motorcycle and track at the top of the loop = 2343.75 N