Question

For an ideal gas mixture of A and B, if the total pressure is 100 kPa and component B has a mole fraction of 0.25, calculate the partial pressure of component

Answer 1

The partial pressure of component A and B is 75 kPa and 25kPa respectively.

Step-by-step explanation:

Total pressure of ideal gas mixture = 100kPa

Mole fraction of component B,
`\chi_B= 0.25`

Mole fraction of component A ,
`\chi_A`

As we know sum of all mole fraction in a mixture is equal to zero.

`\chi_A+\chi+B=1`

`\chi_A=1-\chi_B=1-0.25=0.75`

For partial pressure of each component we will apply Dalton's law of partial pressure:

`p^(o)_i=p_(total)* \chi_i`

Partial pressure of component a in a mixture:

`p^(o)_A=p* \chi_A=100kPa* 0.75=75 kPa`

Partial pressure of component a in a mixture:

`p^(o)_B=p* \chi_B=100kPa* 0.25=25 kPa`