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How much work in joules must be done to stop a 920-kg car traveling at 90 km/h?

1 Answer

7 votes

Answer:

Work done, W = −287500 Joules

Step-by-step explanation:

It is given that,

Mass of the car, m = 920 kg

The car is travelling at a speed of, u = 90 km/h = 25 m/s

We need to find the amount of work must be done to stop this car. The final velocity of the car, v = 0

Work done is also defined as the change in kinetic energy of an object i.e.


W=\Delta K


W=(1)/(2)m(v^2-u^2)


W=(1)/(2)* 920\ kg(0-(25\ m/s)^2)

W = −287500 Joules

Negative sign shows the work done is done is opposite direction.

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