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The 0.41-kg cup of a James Bond anti-Martini-Maker is attached to a spring of spring constant 110 N/m. The cup is displaced horizontally from the equilibrium position and let go. What is the period of martini oscillation? A) 0.023 s B) 0.38 s C) 0.80s D) 100 s

User Mkingston
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Answer:

Option B is the correct answer.

Step-by-step explanation:

Period of a spring is given by the expression


T=2\pi \sqrt{(m)/(k)}

Here, spring constant, k = 110 N/m

Mass = 0.41 kg

Substituting,


T=2\pi \sqrt{(m)/(k)}=2\pi \sqrt{(0.41)/(110)}=0.38s

Option B is the correct answer.